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For the given values of initial velocity of projection and angle...

This question belongs to Civil Engineering Applied Mechanics And Graphic Statics
Applied Mechanics and Graphic Statics
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For the given values of initial velocity of projection and angle of inclination of the plane, the maximum range for a projectile projected upwards will be obtained, if the angle of projection is

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Correct Answer: Option B
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2 Comments
Civil Engineering
Civil Engineering 10 months ago
1. If (lpha ) is measured from the HORIZONTAL: The correct answer is indeed (lpha = rac{pi }{4}+ rac{eta }{2}). Reasoning: To maximize range up an incline, you must "split the difference" between the vertical ((90^{circ })) and the incline itself ((eta )). The angle halfway between (eta ) and (90^{circ }) is ( rac{90+eta }{2}=45^{circ }+ rac{eta }{2}).This matches Exam Veda's Option B. 2. If (lpha ) is measured from the INCLINED PLANE: The correct answer is (lpha = rac{pi }{4}- rac{eta }{2}). Reasoning: If ( heta ) is the angle from the horizontal and (lpha ) is the angle relative to the plane, then ( heta =lpha +eta ). Substituting the horizontal condition ((45^{circ }+ rac{eta }{2})) into this gives:(lpha +eta =45^{circ }+ rac{eta }{2}implies lpha =45^{circ }- rac{eta }{2})This matches Option A.
Amit Kumar
Amit Kumar 7 years ago
Please provide solution.....
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