Harmonic mean temperature difference is given by
A. $$\sqrt {\Delta {{\text{T}}_1} \cdot \Delta {{\text{T}}_2}} $$
B. $$\frac{{2 \cdot \Delta {{\text{T}}_1} \cdot \Delta {{\text{T}}_2}}}{{\Delta {{\text{T}}_1} + \Delta {{\text{T}}_2}}}$$
C. $$\frac{{2 \cdot \Delta {{\text{T}}_1} \cdot \Delta {{\text{T}}_2}}}{{\Delta {{\text{T}}_1} - \Delta {{\text{T}}_2}}}$$
D. $$\frac{{\Delta {{\text{T}}_1} - \Delta {{\text{T}}_2}}}{{\Delta {{\text{T}}_1} \cdot \Delta {{\text{T}}_2}}}$$
Answer: Option B
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