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Comments ( 18 )

  1. Indra Dev
    Indra Dev :
    1 year ago

    Mujhe samajhane ki kripya pradhan kare

  2. Prathamesh Ahire
    Prathamesh Ahire :
    1 year ago

    Hi guys I am prathamesh ahire
    And I am trying to solve this question

    Width- 30 km
    Flight lines - 16
    Therefore total flights - 15
    Then width of 1 (one) flight - 30/15 = 2 km
    As given scale is 1:50000 ( means 1cm = 50000 cm )
    We know that , 1 km = 100000 cm
    Therefore , for 2km scale will be 4 cm

  3. Jajwinder Singh
    Jajwinder Singh :
    2 years ago

    Harman bajwa right ans

  4. Ankur Bhattacharya
    Ankur Bhattacharya :
    2 years ago

    D

  5. Aaman Momin
    Aaman Momin :
    2 years ago

    How it is.?

  6. Manash Pratim
    Manash Pratim :
    2 years ago

    16 lines divide the area to 15 spacings, so
    Distance / spacing = 30/15.
    Equate it with (map/ground)
    =>1/50,000= x/ (3/15)
    X= 4cm

  7. Jajwinder Singh
    Jajwinder Singh :
    2 years ago

    Abhijit kumar

  8. Makhan Rajwal
    Makhan Rajwal :
    2 years ago

    I want to discuss this question

  9. Md Nahid
    Md Nahid :
    2 years ago

    [30÷(16-1)]×1000×100÷50000=4

  10. Abhijit Kumar
    Abhijit Kumar :
    2 years ago

    30 km = 30 x 1000 x 100 cm
    Scale on Map = 1: 50,000
    Area on Map = (30 x 1000 x 100)/50000 = 60
    IF 16 lines divide the area into 15 parts, then 60/15 = 4
    i.e. Distance between two flights is 4 cm

  11. Abhijit
    Abhijit :
    2 years ago

    Flight lines = (Width(coverage)/spacing)
    16 = (30,000/x)
    x = 30,000 / 16
    x = 1875
    scale = map/ ground
    1/50,000 = x / 1875
    x = 0.0375 m = 3.75 cm ~~ 4cm

  12. Abhijit
    Abhijit :
    2 years ago

    Flight lines = (Width(coverage)/spacing)
    16 = (30,000/x)
    x = 30,000 / 16
    x = 1875
    scale = map/ ground
    1/50,000 = x / 1875
    x = 0.0375 m = 3.75 cm ~~ 4cm

  13. Sudheer Immadisetty
    Sudheer Immadisetty :
    2 years ago

    Yes

  14. Harman Bajwa
    Harman Bajwa :
    2 years ago

    30,000/16=1875

    1875/50,000 m =0.0375 Cm
    ~~4 cm

  15. Bishwajit Biswal
    Bishwajit Biswal :
    3 years ago

    reason??# of Flight lines = (Width(coverage)/spacing)
    16 = (30,000/x)
    x = 30,000 / 16
    x = 1875
    scale = map/ ground
    1/50,000 = x / 1875
    x = 0.0375 m = 3.75 cm ~~ 4cm

  16. MD MANZER
    MD MANZER :
    3 years ago

    (30*100000)/(50000*(16-1))=4cm

  17. John Louie
    John Louie :
    4 years ago

    # of Flight lines = (Width(coverage)/spacing)
    16 = (30,000/x)
    x = 30,000 / 16
    x = 1875
    scale = map/ ground
    1/50,000 = x / 1875
    x = 0.0375 m = 3.75 cm ~~ 4cm

  18. Sunil Choudhary
    Sunil Choudhary :
    4 years ago

    ??

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