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1
If 16 flight lines are run perpendicular to an area 30 km wide, their spacings on a photographical map on scale 1 : 50,000 , will be
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Answer & Solution
Answer: Option D
Solution:
Let's break down this surveying problem step by step!

First, we need to understand what the question is asking.
It's about the spacing between flight lines on a map, given a real-world area and a map scale.

The area's width is 30 km, and there are 16 flight lines perpendicular to it. This means the 16 flight lines divide the 30 km width into 15 equal spaces.
Therefore, the spacing between the flight lines on the *ground* is calculated as: 30 km / 15 = 2 km.

Next, we need to convert this ground distance to the map distance using the scale 1:50,000.
This scale means that 1 unit on the map represents 50,000 units on the ground.

Convert the ground distance (2 km) to centimeters: 2 km = 2 * 1000 m = 2 * 1000 * 100 cm = 200,000 cm.

Now, apply the scale to find the map distance: Map distance = Ground distance / Scale factor = 200,000 cm / 50,000 = 4 cm.

Therefore, the spacing between the flight lines on the photographical map will be 4 cm.

So, the correct answer is: Option D: 4 cm.
2
Which of the following methods of contouring is most suitable for a hilly terrain?
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Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
3
The size of a plane table is
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Answer & Solution
Answer: Option B
Solution:
The size of a plane table is typically 600 mm × 750 mm.

Plane tables are surveying instruments used for mapping and plotting, and their standard dimensions are often 600 mm × 750 mm.

This size provides a suitable working area for accurate and detailed plotting of survey data.

Other sizes mentioned are not standard for plane tables used in surveying.
4
The angle between the plane of the equator and the plane of the ecliptic, is known as obliquity of the ecliptic and its value is
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Answer & Solution
Answer: Option B
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5
For a tacheometer the additive and multi-plying constants are respectively
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Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
6
From the principal point the horizon point lies on the principal line at a distance of
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Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
7
If the magnetic bearing of the sun at a place at noon in southern hemisphere is 167°, the magnetic declination at that place is
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Answer & Solution
Answer: Option C
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8
Overturning of vehicles on a curve can be avoided by using
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Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
9
The error due to eccentricity of inner and outer axes can be eliminated by
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Answer & Solution
Answer: Option A
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10
The Polaris remains below horizon at
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Answer & Solution
Answer: Option D
Solution:
The correct answer is Option D: 5° S latitude.
Here's why:
Polaris, also known as the North Star, is located very close to the North Celestial Pole.
The altitude of the North Celestial Pole above the horizon is equal to the observer's latitude in the Northern Hemisphere.
If you are at the Equator (0° latitude), Polaris will be right on the horizon.
As you move northward, Polaris appears higher and higher in the sky.
However, Polaris can only be seen from locations in the Northern Hemisphere or very close to the equator.
If you are in the Southern Hemisphere, Polaris will be below the horizon.
Since 5° S latitude is in the Southern Hemisphere, Polaris will be below the horizon there.
At 10° N and 50° N latitude, Polaris will be visible above the horizon.
At the Equator, Polaris will be on the horizon.