If a 30 m ladder is placed against a 15 m wall such that it just reaches the top of the wall, then the elevation of the wall is equal to-
A. 45°
B. 30°
C. 60°
D. 50°
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {\text{AC = 30 meter}} \cr & {\text{AB = 15 meter}} \cr & \angle {\text{ACB}} = \theta \cr & \therefore \sin \theta = \frac{{AB}}{{AC}} = \frac{{15}}{{30}} = \frac{1}{2} \cr & \Rightarrow \sin \theta = \sin {30^ \circ } \cr & \Rightarrow \theta = {30^ \circ } \cr} $$
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i am having a doubt, The angle of elevation with the wall right.. so theta should be taken as angle CAB. Here, u have taken it as ACB which means the angle of elevation of the ladder with the ground. I want to clarify this. Pls reply at the earliest
the above option which u have kept is wrong