If a hollow sphere of internal and external diameters 4 cm and 8 cm respectively is melted into a cylinder of base diameter 8 cm, then the height of the cylinder is :
A. 4 cm
B. $$\frac{13}{3}$$ cm
C. $$\frac{14}{3}$$ cm
D. 5 cm
Answer: Option C
Solution(By Examveda Team)
Let the height of the cylinder be h cmThen,
$$\eqalign{ & \frac{4}{3}\pi \left[ {{{\left( 4 \right)}^3} - {{\left( 2 \right)}^3}} \right] = \pi \times {4^2} \times h \cr & \Rightarrow \frac{4}{3} \times \pi \times 56 = \pi \times 16h \cr & \Rightarrow h = \frac{{4 \times 56}}{{3 \times 16}} \cr & \Rightarrow h = \frac{{14}}{3}\,cm \cr} $$
Related Questions on Volume and Surface Area
A. 12$$\pi$$ cm3
B. 15$$\pi$$ cm3
C. 16$$\pi$$ cm3
D. 20$$\pi$$ cm3
In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
A. 75 cu. m
B. 750 cu. m
C. 7500 cu. m
D. 75000 cu. m
A. 84 meters
B. 90 meters
C. 168 meters
D. 336 meters
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