If a right circular cone is separated into solids of volumes V1, V2, V3 by two planes parallel to the base which also trisect the altitude, then V1 : V2 : V3 is
A. 1 : 2 : 3
B. 1 : 4 : 6
C. 1 : 6 : 9
D. 1 : 7 : 19
Answer: Option D
Solution (By Examveda Team)
Ratio of volume of bigger cone and smaller cone= (Ratio of altitude)2
= (1 : 2 : 3)3
= (1 : 8 : 27)
∴ Ratio of parts
= 1 : 8 - 1 : 27 - 8
= 1 : 7 : 19
This Question Belongs to Arithmetic Ability >> Mensuration 3D
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