If an atom is in the 3d3 state, the angle between its orbital and spin angular momentum vectors ($$\overrightarrow {\bf{L}} $$ and $$\overrightarrow {\bf{S}} $$) is
A. $${\cos ^{ - 1}}\frac{1}{{\sqrt 3 }}$$
B. $${\cos ^{ - 1}}\frac{2}{{\sqrt 3 }}$$
C. $${\cos ^{ - 1}}\frac{1}{2}$$
D. $${\cos ^{ - 1}}\frac{{\sqrt 3 }}{2}$$
Answer: Option A
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