If θ and δ be the latitude of an observer and declination of a heavenly body respectively, the upper culmination of the body will be south of zenith if its zenith distance, is
A. δ - θ
B. θ - δ
C. θ + δ
D. $$\frac{1}{2}$$ (θ - δ)
Answer: Option B
This Question Belongs to Civil Engineering >> Surveying
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