If E is the spherical excess and R the radius of the earth, the surface area of the triangle, is

A. $$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{90}^ \circ }}}$$

B. $$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{180}^ \circ }}}$$

C. $$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{270}^ \circ }}}$$

D. $$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{360}^ \circ }}}$$

Answer: Option B