If mercury in a barometer is replaced by water, the height of 3.75 cm of mercury will be following cm of water
A. 51 cm
B. 50 cm
C. 52 cm
D. 52.2 cm
Answer: Option A
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Related Questions on Hydraulics and Fluid Mechanics
A. 22.5 m/sec.
B. 33 m/sec.
C. 40 m/sec.
D. 90 m/sec.
A. the weight of the body
B. more than the weight of the body
C. less than the weight of the body
D. weight of the fluid displaced by the body
The difference of pressure between the inside and outside of a liquid drop is
A. $${\text{p}} = {\text{T}} \times {\text{r}}$$
B. $${\text{p}} = \frac{{\text{T}}}{{\text{r}}}$$
C. $${\text{p}} = \frac{{\text{T}}}{{2{\text{r}}}}$$
D. $${\text{p}} = \frac{{2{\text{T}}}}{{\text{r}}}$$
A. cannot be subjected to shear forces
B. always expands until it fills any container
C. has the same shear stress.at a point regardless of its motion
D. cannot remain at rest under action of any shear force
p= qgh
p= 13.6*10*3.75 =510
510 = 1*10*h
h = 51cm
Pressure of mercury = pressure of water
Density x g x h = Density x g x h
13600 x 9.81 x 3.75 = 1000 x 9.81 x h
h = 51cm
How?