If the height of a vertical pole is $$\sqrt 3 $$ times the length of its shadow on the ground, then the angle of elevation of the sun at that time is

A. 30°

B. 60°

C. 45°

D. 75°

Answer: Option B

Solution(By Examveda Team)

Let AB be a vertical pole and let its shadow be BC

Let BC = x m, then length of pole = $$\sqrt 3 $$ x,
$$\theta $$ be the angle of elevation
$$\eqalign{ & \therefore {\text{tan}}\theta = \frac{{AB}}{{BC}} = \frac{{\sqrt 3 \,x}}{x} = \sqrt 3 \cr & = \tan {60^ \circ } \cr & \therefore \theta = {60^ \circ } \cr} $$