If the magnetic bearing of the sun at a place at noon in southern hemisphere is 167°, the magnetic declination at that place is
A. 77° N
B. 23° S
C. 13° E
D. 13° W
Answer: Option C
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C
At noon means 12 PM. the sun is exactly at the poles or you must be knowing its actually overhead. Since in question it says in Southern hemisphere, therefore it lies exactly at south pole ( True south), thus true bearing of sun becomes 180 degree and since magnetic bearing given as 167 degree. it being less implies that magnetic north will lie to the east of true north. thus declination = (True bearing - Magnetic bearing) = 13*E
At noon means 12 PM. the sun is exactly at the poles or you must be knowing its actually overhead. Since in question it says in Southern hemisphere, therefore it lies exactly at south pole ( True south), thus true bearing of sun becomes 180 degree and since magnetic bearing given as 167 degree. it being less implies that magnetic north will lie to the east of true north. thus declination = (True bearing - Magnetic bearing) = 13*E
Pls send me Method of solving
T.B.=M.B.+Declination if east
T.B.=M.B. - Declination if west
180=167+13