If the ordinate and abscissa of the point (k, 2k - 1) be equal, then the value of k is:
A. 0
B. -1
C. 1
D. $$\frac{1}{2}$$
Answer: Option C
Solution (By Examveda Team)
Since ordinate = abscissa∴ k = 2k - 1
k = 1
Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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