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If the product of three consecutive integers is 120, then the sum of the integers is :
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& 120: \cr
& = 2 \times 2 \times 2 \times 3 \times 5 \cr
& = \left( {2 \times 2} \right) \times 5 \times \left( {2 \times 3} \right) \cr
& = 4 \times 5 \times 6 \cr} $$
Clearly, the three consecutive integers whose product is 120 are 4, 5 and 6
Required sum :
= 4 + 5 + 6
= 15
Clearly, the three consecutive integers whose product is 120 are 4, 5 and 6
Required sum :
= 4 + 5 + 6
= 15
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