If the radii of the circular ends of a frustum which is 45 cm high be 28 cm and 7 cm then the capacity of the bucket in cubic centimetre is. $$\left( {{\text{Use }}\pi = \frac{{22}}{7}} \right)$$

Solution (By Examveda Team)

$$\eqalign{ & {\text{Volume of bucket}} \cr & = \frac{1}{3}\pi h\left( {{R^2} + {r^2} + Rr} \right) \cr & = \frac{1}{3} \times \frac{{22}}{7} \times 45\left( {{{28}^2} + {7^2} + 28 \times 7} \right) \cr & = \frac{{22}}{7} \times 15 \times 1029 \cr & = 48510{\text{ c}}{{\text{m}}^3} \cr} $$