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If the radius of the base of a right circular cylinder is increased by 20% and the height is decreased by 30%, then what is the percentage increase/decrease in the volume?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& V = \frac{1}{3}\pi {r^2}h \cr
& r \to 20\% \to \frac{{ + 1}}{5} \cr
& h \to 30\% \to \frac{{ - 3}}{{10}} \cr
& {r^2} \Rightarrow {5^2}:{6^2} \cr
& h \Rightarrow 10:7 \cr
& V \Rightarrow 250:252 \cr
& {\text{Increase}} = 2 \cr
& {\text{Increase }}\% = \frac{2}{{250}} \times 100 = 0.8\% \cr} $$
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