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If the sum of a number and its square is 182, what is the number ?
Answer & Solution
Correct Answer:
Option
E
Let the number be x
Then,
$$\eqalign{ & \Leftrightarrow x + {x^2} = 182 \cr & \Leftrightarrow {x^2} + x - 182 = 0 \cr & \Leftrightarrow \left( {x + 14} \right)\left( {x - 13} \right) = 0 \cr & \Leftrightarrow x = 13 \cr} $$
Then,
$$\eqalign{ & \Leftrightarrow x + {x^2} = 182 \cr & \Leftrightarrow {x^2} + x - 182 = 0 \cr & \Leftrightarrow \left( {x + 14} \right)\left( {x - 13} \right) = 0 \cr & \Leftrightarrow x = 13 \cr} $$
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Login=X(1+1²)=182
=2x=182
=X=182/2
=X=91
Is it wrong?