If two incorrect watches are set at 12:00 noon at correct time, when will both watches show the correct time for the first time given that the first watch gains 1 min in one hour and second watch looses 4 min in two hours.
A. 6 PM, 25 days later
B. 12 noon, 30 days later
C. 12 noon, 15 days later
D. 6 AM, 45 days later
E. None of these
Answer: Option B
Solution(By Examveda Team)
First watch: It shows correct time when it creates difference of 12 hours. So, to create difference of 12 hour, time required = $$\frac{{60 \times 12}}{{24}}$$ = 30 daysSecond watch: It shows correct time when it creates difference of 12 hours. So, to create difference of 12 hour, time required = $$\frac{{30 \times 12}}{{24}}$$ = 15 days Now, LCM of 30 and 15 gives the time when they show correct time together. Thus, required time = 30 days, at same time.
Join The Discussion
Comments ( 2 )
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
How it is known that watches will show correct time when they create a difference of 12 hrs
It's a Wrong Answer. The answer is 10 days