Examveda
Examveda

If velocity is zero over $${\frac{1}{3}^{{\text{rd}}}}$$ of a cross-section and is uniform over remaining $${\frac{2}{3}^{{\text{rd}}}}$$ of the cross-section, then the correction factor for kinetic energy is

A. $$\frac{4}{3}$$

B. $$\frac{3}{2}$$

C. $$\frac{9}{4}$$

D. $$\frac{{27}}{8}$$

Answer: Option C


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Comments ( 3 )

  1. Culprit
    Culprit :
    3 years ago

    Ua=(2/3).Umax
    KE correction Fctr= (umax³ .(2/3 A))/(ua³)(A)
    = 9/4

  2. UPSC
    UPSC :
    3 years ago

    How to get the answer?

  3. Rohan Sinha
    Rohan Sinha :
    5 years ago

    How we get this answer

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