If velocity is zero over $${\frac{1}{3}^{{\text{rd}}}}$$ of a cross-section and is uniform over remaining $${\frac{2}{3}^{{\text{rd}}}}$$ of the cross-section, then the correction factor for kinetic energy is
A. $$\frac{4}{3}$$
B. $$\frac{3}{2}$$
C. $$\frac{9}{4}$$
D. $$\frac{{27}}{8}$$
Answer: Option C

Ua=(2/3).Umax
KE correction Fctr= (umax³ .(2/3 A))/(ua³)(A)
= 9/4
How to get the answer?
How we get this answer