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In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:

A. 1 hour

B. 2 hours

C. 3 hours

D. 4 hours

Answer: Option A

Solution(By Examveda Team)

$$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{duration}}\,{\text{of}}\,{\text{the}}\,{\text{flight}}\,{\text{be}}\,x\,{\text{hours}} \cr & {\text{Then}},\frac{{600}}{x} - \frac{{600}}{{x + \left( {1/2} \right)}} = 200 \cr & \Rightarrow \frac{{600}}{x} - \frac{{1200}}{{2x + 1}} = 200 \cr & \Rightarrow x\left( {2x + 1} \right) = 3 \cr & \Rightarrow 2{x^2} + x - 3 = 0 \cr & \Rightarrow (2x + 3)(x - 1) = 0 \cr & \Rightarrow x = 1\,\text{hour} \cr} $$

This Question Belongs to Arithmetic Ability >> Speed Time And Distance

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Comments ( 3 )

  1. Sheikh Likhon
    Sheikh Likhon :
    4 years ago

    The answer is 1.5 hour please check your answer
    Examveda

  2. Ashraful Islam
    Ashraful Islam :
    5 years ago

    Let,the speed of flight = x km/hr
    So,
    600/(x-200) - 600/x = 1/2
    => (x-x+200)/x(x-200) = 1/1200
    => 1/(x^2-200x) = 1/1200*200
    => x^2 - 200x - 400*600 = 0
    => (x+400)(x-600) = 0
    => x = 600 km/hr
    Duration of flight = 600km/600km/hr = 1hr

  3. Ashraful Islam
    Ashraful Islam :
    5 years ago

    Let,the speed of flight = x km/hr
    So,
    600/(x-200) - 600/x = 1/2
    => (x-x+200)/x(x-200) = 1/1200
    => 1/(x^2-200x) = 1/1200*200
    => x^2 - 200x - 400*600 = 0
    => (x+400)(x-600) = 0
    => x = 600 km/hr
    Duration of flight = 600km/600km/hr = 1hr

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