ExamVeda
Login
Home
Applied Mechanics and Graphic Statics
?

In a lifting machine a weight of 5 kN is lifted through 200 mm by an effort of 0.1 kN moving through 15 m. The mechanical advantage and velocity ratio of the machine are respectively

Answer & Solution
Correct Answer: Option A
Let's discuss the solution. Join the discussion
Examveda
Question posted by Examveda
Community

Join the Discussion

1 Comment
Rai Pratibha
Rai Pratibha 6 years ago
Mechanical advantage = weight/ effort
Velocity ratio=15/0.2
200 mm= 0.2 m