In a right circular cone, the radius of its base is 7 cm and its height is 24 cm. A cross-section is made through the mid-point of the height parallel to the base. The volume of the upper portion is :
A. 154 cm3
B. 169 cm3
C. 800 cm3
D. 1078 cm3
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & r = 7{\text{ cm, }}h{\text{ = 24 cm}} \cr & {\text{Now, }}\vartriangle {\text{AOB}} \sim \vartriangle {\text{COD}} \cr & {\text{So, }}\frac{{OA}}{{OC}} = \frac{{AB}}{{CD}} \cr & \Rightarrow \frac{h}{{\frac{h}{2}}} = \frac{r}{{CD}} \cr & \Rightarrow CD = \frac{r}{2} \cr} $$
∴ Volume of upper portion :
$$\eqalign{ & = \frac{1}{3}\pi {\left( {\frac{r}{2}} \right)^2}\left( {\frac{h}{2}} \right) \cr & = \left( {\frac{1}{3} \times \frac{{22}}{7} \times \frac{7}{2} \times \frac{7}{2} \times 12} \right){\text{ c}}{{\text{m}}^3} \cr & = 154{\text{ c}}{{\text{m}}^3} \cr} $$
Related Questions on Volume and Surface Area
A. 12$$\pi$$ cm3
B. 15$$\pi$$ cm3
C. 16$$\pi$$ cm3
D. 20$$\pi$$ cm3
In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
A. 75 cu. m
B. 750 cu. m
C. 7500 cu. m
D. 75000 cu. m
A. 84 meters
B. 90 meters
C. 168 meters
D. 336 meters
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