In a two dimensional incompressible steady flow around an airfoil, the stream lines are 2 cm apart at a great distance from the airfoil, where the velocity is 30 m/sec. The velocity near the airfoil, where the stream lines are 1.5 cm apart, is
A. 22.5 m/sec.
B. 33 m/sec.
C. 40 m/sec.
D. 90 m/sec.
Answer: Option C
A1V1 = A2V2
0.02 x 30 = 0.015 x v2
v2 = 0.02 x30 / 0.015
v2 = 40 m/sec
X×1.5=30×2
X=(30×2)/1.5
X=40m/sec
How to calculate?
how??
vr=constant
v1r1=v2r2
30*2=1.5*v2
v2=40m/s
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