In Joule's experiment an insulated container contains 20 kg of water...

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In Joule's experiment, an insulated container contains 20 kg of water initially at 25°C. It is stirred by an agitator, which is made to turn by a slowly falling body weighing 40 kg through a height of 4 m. The process is repeated 500 times. The acceleration due to gravity is 9.8 ms^-2. Neglecting the heat capacity of agitator, the temperature of water (in °C) is

A. 40.5

B. 34.4

C. 26.8

D. 25

Answer: Option B

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Comments ( 3 )

Sirisha Usha :

3 years ago

Energy added to water=500*40*9.8*4J=784000J
Let the T of water 20*4180(T-25) =784000J
T=34.4C
Prayashee Borah :

4 years ago

Please give the solution ...how can solve this
Parth Mehta :

4 years ago

Cannot understand the given system

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