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Latent heat absorbed by 1 lb of water at 212°F, when it is changed to steam at 212°F, may be around __________ BTU.

A. 180

B. 970

C. 3.97

D. None of these

Answer: Option A


This Question Belongs to Chemical Engineering >> Heat Transfer

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Comments (2)

  1. Atanu Chatterjee
    Atanu Chatterjee:
    4 months ago

    The correct answer is:

    B. 970

    Explanation:
    Latent heat of vaporization is the amount of heat required to convert a liquid into vapor without a change in temperature.

    For water at 212°F (100°C) and standard atmospheric pressure:

    The latent heat of vaporization ≈ 970 BTU/lb

    This is the heat required to convert 1 lb of water at 212°F into 1 lb of steam at 212°F.

    Other Options:
    A. 180 BTU → This is the sensible heat to raise water from 32°F to 212°F.

    C. 3.97 BTU → Irrelevant value.

    D. None of these → Incorrect, since B is valid.

    ✅ Final Answer: B. 970

  2. Waqas Faizan
    Waqas Faizan:
    9 months ago

    The latent heat of vaporization (also known as enthalpy of vaporization) for water at atmospheric pressure (212°F) is approximately 970 BTU per pound. so Answer is B

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