Answer & Solution
Answer: Option A
No explanation is given for this question Let's Discuss on Board
42. A dislocation line in a fcc crystal dissociates into two partials which have their Burger vectors as $$\frac{a}{6}\left[ {2\overline 1 \overline 1 } \right]$$ and $$\frac{a}{6}\left[ {11\overline 2 } \right],$$ Indicate the correct statement.
43. In a single crystal of copper (lattice parameter 3.615°A). The distance between (11) planes (in °A) is
44. Match the following metals and alloys with their slip planes for room temperature deformations.
P. Austenitic stainless steel
1. None
Q. Molybednum
2. (110)
R. Cadmium
3. (111)
S. Tin
4. (0001)
| P. Austenitic stainless steel | 1. None |
| Q. Molybednum | 2. (110) |
| R. Cadmium | 3. (111) |
| S. Tin | 4. (0001) |
45. The respective units for dislocation density and stress intensity factor are
46. In a cubic lattice, the direction [123] is contained in the
47. Shear modulus of copper is 45 GPa. Lattice parameter of copper is 3.61°A. The magnitude of burgers vector in copper is . . . . . . . . °A.
48. The direction [011] in cubic crystals
49. For an FCC metal, the ratio of interplanar spacing obtained from the first two peaks of the X-ray diffraction pattern is
50. Which of the following statements are true about edge dislocations?
P. Edge dislocations do not have an extra half plane associated with them.
Q. The Burger vectors is perpendicular to the direction.
R. Edge dislocations can avoid obstacles by cross-slip.
S. Depending on geometry, parallel edge dislocations of opposite signs can attract or repel one another.
P. Edge dislocations do not have an extra half plane associated with them.
Q. The Burger vectors is perpendicular to the direction.
R. Edge dislocations can avoid obstacles by cross-slip.
S. Depending on geometry, parallel edge dislocations of opposite signs can attract or repel one another.