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N solid metallic spherical balls are melted and recast into a cylindrical rod whose radius is 3 times that of a spherical ball and height is 4 times the radius of a spherical ball. The value of N is:
Answer & Solution
Correct Answer:
Option
B
\[\begin{array}{*{20}{c}}
{}&{{\text{Sphere}}}&{}&{{\text{Cylinder}}} \\
{{\text{Radius}} \to }&R&:&{3R} \\
{{\text{Height}} \to }& - &{}&{4R}
\end{array}\]
$$\eqalign{ & N \times \frac{4}{3}\pi {R^3} = \pi {\left( {3R} \right)^2} \times 4R \cr & N \times \frac{4}{3}{R^3} = 3 \times 4{R^3} \cr & N = 27 \cr} $$
$$\eqalign{ & N \times \frac{4}{3}\pi {R^3} = \pi {\left( {3R} \right)^2} \times 4R \cr & N \times \frac{4}{3}{R^3} = 3 \times 4{R^3} \cr & N = 27 \cr} $$
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