Narayan walking at a speed of 20 km/h reaches his college 10 minutes late. Next time he increases his speed by 5 km/h, but finds that he is still late by 4 minutes. What is the distance of his college from his house?
A. 10 km
B. 6 km
C. 12 km
D. 15 km
Answer: Option A
Solution(By Examveda Team)
By increasing his speed by 25%, he will reduce his time by 20%. (This corresponds to a 6 minutes drop in his time.) Hence, his time originally must have been 30 minutes. Thus required distance = 20 kmph × 0.5 hours = 10 km.This Question Belongs to Arithmetic Ability >> Speed Time And Distance
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Comments ( 3 )
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
Assume that he should reach in x minutes
Let first he will reach in x + 10 minutes
Next time he will reach in x + 4 min
We know that distance = speed x time
In first case we get
distance = 20(x + 10)
= 20 x + 200
So in the second case
distance = 25 (x + 4)
= 25 x + 100
Equating both we get
20 x + 200 = 25 x + 100
5 x = 100
x = 20 min (actual time)
So in I case he will reach by x + 10 = 20 + 10 = 30 min
So in 1 hour he will travel 20 kms
So in 30 min he will travel 20 x 30 / 60 = 10 kms
Read more on Brainly.in - https://brainly.in/question/6020722#readmore
1st approach:
s=20:25
t=25:20=5:4=30:24
d=20/2=10 km/hr...(ans)
2nd approach:
20*25/25-20*1/10=10 km/hr
he will reduce his time by 20%...how you calculated this??