The equation of a parabolic arch of span $$l$$ and rise h, is given by
A. $${\text{y}} = \frac{{\text{h}}}{{{l^2}}} \times \left( {1 - {\text{x}}} \right)$$
B. $${\text{y}} = \frac{{2{\text{h}}}}{{{l^2}}} \times \left( {1 - {\text{x}}} \right)$$
C. $${\text{y}} = \frac{{3{\text{h}}}}{{{l^2}}} \times \left( {1 - {\text{x}}} \right)$$
D. $${\text{y}} = \frac{{4{\text{h}}}}{{{l^2}}} \times \left( {1 - {\text{x}}} \right)$$
Answer: Option D
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A. $$\frac{2}{3}$$
B. $$\frac{3}{2}$$
C. $$\frac{5}{8}$$
D. $$\frac{8}{5}$$
Principal planes are subjected to
A. Normal stresses only
B. Tangential stresses only
C. Normal stresses as well as tangential stresses
D. None of these
A. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
B. $$\frac{{\text{I}}}{{\text{M}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
C. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{F}}}{{\text{Y}}}$$
D. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{Y}}}{{\text{F}}}$$
A. $$\frac{{\text{M}}}{{\text{T}}}$$
B. $$\frac{{\text{T}}}{{\text{M}}}$$
C. $$\frac{{2{\text{M}}}}{{\text{T}}}$$
D. $$\frac{{2{\text{T}}}}{{\text{M}}}$$
correct equation is 4hx/l² × (L-x)