Perimeter of a rectangular field is 160 metres and the difference between its two adjacent sides is 48 metres. The side of a square field, having the same area as that of the rectangle, is :
A. 4 metres
B. 8 metres
C. 16 metres
D. 32 metres
Answer: Option D
Solution(By Examveda Team)
Let the sides of the rectangle be x metres and (x + 48) metresThen,
$$\eqalign{ & 2\left( {x + x + 48} \right) = 160 \cr & \Rightarrow 4x + 96 = 160 \cr & \Rightarrow 4x = 64 \cr & \Rightarrow x = 16 \cr} $$
So, sides of the rectangle are 16 metres and 64 metres
Area of the rectangle :
= (16 × 64) m2
= 1024 m2
Area of the square = 1024 m2
∴ Side of the square :
= $$\sqrt {1024} $$ m
= 32 metres
Related Questions on Area
A. 15360 m2
B. 153600 m2
C. 30720 m2
D. 307200 m2
E. None of these
A. 2%
B. 2.02%
C. 4%
D. 4.04%
E. None of these
A. 16 cm
B. 18 cm
C. 24 cm
D. Data inadequate
E. None of these
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
A. 40%
B. 42%
C. 44%
D. 46%
Join The Discussion