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Points A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the cars travel in the same direction, they meet in 5 hours. If the cars travel towards each other, they meet in 1 hour. What is the speed of the faster car ?

A. 70 km/hr

B. 60 km/hr

C. 80 km/hr

D. 40 km/hr

Answer: Option B

Solution(By Examveda Team)

According to the question,
Let the speed of the faster train = x km/hr
The speed of the slower train = y km/hr
$$\eqalign{ & {\text{Speed = }}\frac{{{\text{Distance}}}}{{{\text{Time}}}} \cr & x + y = \frac{{100}}{1}{\text{ km/hr and }} \cr & x - y = \frac{{100}}{5} = 20{\text{ km/hr}} \cr & x + y = 100.....(i) \cr & x - y = 20.....(ii) \cr} $$
Solve equation (i) and (ii), we get
x = 60 km/hr
y = 40 km/hr
Speed of faster car = 60 km/hr

This Question Belongs to Arithmetic Ability >> Speed Time And Distance

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