Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi's speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi's speed is:
A. 12 km/h
B. 10 km/h
C. 8 km/h
D. 6 km/h
Answer: Option C
Solution (By Examveda Team)
Ajay → (x + 4) kmph.A ________ 60 km _________ B
Ravi → x kmph.
Let the speed of Ravi be x kmph;
Hence, Ajay's speed = (x + 4) kmph;
Distance covered by Ajay = 60 + 12 = 72 km;
Distance covered by Ravi = 60 - 12 = 48 km.
According to question,
$$\eqalign{ & \frac{{72}}{{x + 4}} = \frac{{48}}{x} \cr & {\text{or,}}\,\frac{3}{{x + 4}} = \frac{2}{x} \cr & {\text{or,}}3x = 2x + 8 \cr & {\text{or,}}x = 8\,{\text{kmph}} \cr} $$
This Question Belongs to Arithmetic Ability >> Speed Time And Distance
if time is same ,then speed and distance covered are directly proportional .
S X T = D
here time is same. distance covered by ravi and ajay is 48 and 72 respectable.so speed should be in this proportional which is 4 and 6. difference between speed is 4km/h. so ravi speed is 8 and ajay is 12.
Shortcut any
How ravi speed is 60 +12 if the total distance is 60 km only.