Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi's speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi's speed is:

A. 12 km/h

B. 10 km/h

C. 8 km/h

D. 6 km/h

Answer: Option C

Solution(By Examveda Team)

Ajay → (x + 4) kmph.
A ________ 60 km _________ B
Ravi → x kmph.

Let the speed of Ravi be x kmph;
Hence, Ajay's speed = (x + 4) kmph;
Distance covered by Ajay = 60 + 12 = 72 km;
Distance covered by Ravi = 60 - 12 = 48 km.

According to question,
$$\eqalign{ & \frac{{72}}{{x + 4}} = \frac{{48}}{x} \cr & {\text{or,}}\,\frac{3}{{x + 4}} = \frac{2}{x} \cr & {\text{or,}}3x = 2x + 8 \cr & {\text{or,}}x = 8\,{\text{kmph}} \cr} $$