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Roorkee express normally reaches its destination at 50 km/h in 30 hours. Find the speed at which it travels to reduce the time by 10 hours?

A. 38 km/h

B. 76 km/h

C. 75 km/h

D. 60 km/h

Answer: Option C

Solution(By Examveda Team)

let required speed be S km/h
50 × 30 = S × 20
S = 75 km/h

This Question Belongs to Arithmetic Ability >> Speed Time And Distance

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