Running at $$\frac{5}{4}$$ of his usual speed, an athlete improves his timing by 5 minutes. The time he usually takes to run the same distance is:
A. 30 min.
B. 28 min.
C. 25 min.
D. 23 min.
Answer: Option C
Solution(By Examveda Team)
When the athlete walks at $$\frac{5}{4}$$ of his usual speed then he takes $$\frac{4}{5}$$ of his usual time $$\left( {{\text{As}}\,\,{\text{Speed}}\, \propto \frac{1}{{{\text{Time}}}}} \right)$$ and he saves 5 minutes. → Usual time - $$\frac{4}{5}$$ × usual time = 5 minutes → $$\frac{1}{5}$$ × Usual time = 5 minutes Usual time = 25 minutes.Join The Discussion
Comments ( 3 )
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
v1t1=v2t2
So vt=5v/4(t-5)
4t=5t-25
t=25min
Simple, Multiply the Numerator and denominator with the time provided.
Here, Time = 5 Min
So, 5*5 / 4*5 = 25 / 20
Numerator = Usual time=> (25)
Denominator = Late time =>(20).
clear