Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:
A. Rs. 1550
B. Rs. 1650
C. Rs. 1750
D. Rs. 2000
E. None of these
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{C}}{\text{.I}}{\text{.}}\, = Rs.\,\left[ {4000 \times {{\left( {1 + \frac{{10}}{{100}}} \right)}^2} - 4000} \right] \cr & \,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,\left( {4000 \times \frac{{11}}{{10}} \times \frac{{11}}{{10}} - 4000} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,840 \cr & \therefore {\text{Sum}} = Rs.\,\left( {\frac{{420 \times 100}}{{3 \times 8}}} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,1750 \cr} $$Join The Discussion
Comments ( 2 )
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C.I of 4000 = 400+440 =840
Half of c.i = 420
S.I =420 , P=?
420×100/8×3 =3500/2 = 1750
Friends plz help me to solve the problem