The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. The distance of the car from the tower (in metres) is
A. 50 $$\sqrt 3 $$
B. 150 $$\sqrt 3 $$
C. 100 $$\sqrt 3 $$
D. 75
Answer: Option B
Solution(By Examveda Team)
Let AB be the tower of height 150 mC is car and angle of depression is 30°
Therefore, ∠ACB = 30° (alternate angle)
In right - angled triangle ABC,
$$\eqalign{ & \frac{{BC}}{{AB}} = \cot {30^ \circ } \cr & \Rightarrow \frac{{BC}}{{150}} = \sqrt 3 \cr & \Rightarrow BC = 150\sqrt 3 \,m \cr} $$
That is, distance of the car from the tower is $$150\sqrt 3 \,m$$
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