The angle of depression of a point situated at a distance of 70m from the base of a tower is 60°. The height of the tower is-

A. \[35\sqrt 3 {\text{ m}}\]

B. \[70\sqrt 3 {\text{ m}}\]

C. \[\frac{{70\sqrt 3 }}{3}{\text{ m}}\]

D. \[{\text{70 m}}\]

Answer: Option B

Solution(By Examveda Team)

Length of the tower AB = h meter.
$$\eqalign{ & \angle DAC = \angle ACB = {60^ \circ } \cr & BC = 70{\text{ meter}} \cr & {\text{In }}\vartriangle {\text{ABC,}} \cr & {\text{tan }}{60^ \circ } = \frac{{AB}}{{BC}} \cr & \Rightarrow \sqrt 3 = \frac{h}{{70}} \cr & \Rightarrow h = 70\sqrt 3 {\text{ meter}} \cr} $$