The area (in sq. units) of the triangle formed by the graphs of 8x + 3y = 24, 2x + 8 = y and the x-axis is:
A. 28
B. 14
C. 15
D. 24
Answer: Option A
Solution (By Examveda Team)

$$\eqalign{ & {\text{At }}x{\text{ - axis}},\,y = 0 \cr & 8x + 3y = 24 \cr & x = 3 \cr & 2x + 8 = y \cr & x = - 4 \cr & \,\,\,8x + 3y = 24 \to \left( {\text{i}} \right) \cr & \,\,\,8x - 4y = 32 \to \left( {{\text{ii}}} \right) \cr & \underline {\, - \,\,\,\,\, + \,\,\,\,\,\,\,\,\, + \,\,\,\,\,\,\,\,} \cr & 7y = 56 \cr & y = 8 \cr & {\text{Area}} = \frac{1}{2} \times {\text{base}} \times {\text{height}} \cr & = \frac{1}{2} \times 7 \times 8 \cr & = 28 \cr} $$
Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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