The area of a triangle whose sides are of lengths 3 cm, 4 cm and 5 cm is :

Solution (By Examveda Team)

Since 3² + 4² = 5²,
So it is a right-angled triangle with Base = 3 cm and Height = 4 cm
∴ Area :
$$\eqalign{ & = \left( {\frac{1}{2} \times 3 \times 4} \right)c{m^2} \cr & = 6\,c{m^2} \cr} $$