The area of the greatest circle which can be inscribed in a square whose perimeter is 120 cm, is :
A. $$\frac{{22}}{7} \times {\left( {\frac{7}{2}} \right)^2}c{m^2}$$
B. $$\frac{{22}}{7} \times {\left( {\frac{9}{2}} \right)^2}c{m^2}$$
C. $$\frac{{22}}{7} \times {\left( {\frac{15}{2}} \right)^2}c{m^2}$$
D. $$\frac{{22}}{7} \times {\left( {15} \right)^2}c{m^2}$$
Answer: Option D
Solution (By Examveda Team)
Side of the square :$$\eqalign{ & = \frac{{120}}{4}cm \cr & = 30\,cm \cr} $$
Radius of the required circle :
$$\eqalign{ & = \left( {\frac{1}{2} \times 30} \right)cm \cr & = 15\,cm \cr & = \pi \times {r^2} \cr & = \left[ {\frac{{22}}{7} \times {{\left( {15} \right)}^2}} \right]c{m^2} \cr} $$
This Question Belongs to Arithmetic Ability >> Area
Join The Discussion