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The area of the greatest circle which can be inscribed in a square whose perimeter is 120 cm, is :
Answer & Solution
Correct Answer:
Option
D
Side of the square :
$$\eqalign{ & = \frac{{120}}{4}cm \cr & = 30\,cm \cr} $$
Radius of the required circle :
$$\eqalign{ & = \left( {\frac{1}{2} \times 30} \right)cm \cr & = 15\,cm \cr & = \pi \times {r^2} \cr & = \left[ {\frac{{22}}{7} \times {{\left( {15} \right)}^2}} \right]c{m^2} \cr} $$
$$\eqalign{ & = \frac{{120}}{4}cm \cr & = 30\,cm \cr} $$
Radius of the required circle :
$$\eqalign{ & = \left( {\frac{1}{2} \times 30} \right)cm \cr & = 15\,cm \cr & = \pi \times {r^2} \cr & = \left[ {\frac{{22}}{7} \times {{\left( {15} \right)}^2}} \right]c{m^2} \cr} $$
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