The area of two similar triangles are 12 cm2 and 48 cm2. If the height of the smaller one is 2.1 cm, then the corresponding height of the bigger one is :
A. 0.525 cm
B. 4.2 cm
C. 4.41 cm
D. 8.4 cm
Answer: Option B
Solution(By Examveda Team)
Note : The areas of two similar triangles are in the ratio of the squares of the corresponding altitudes. Let the length of the required altitude be x cmThen,
$$\eqalign{ & \frac{{12}}{{48}} = \frac{{{{\left( {2.1} \right)}^2}}}{{{x^2}}} \cr & \Rightarrow {x^2} = \left( {4.41 \times 4} \right) \cr & \Rightarrow x = 2.1 \times 2 \cr & \Rightarrow x = 4.2\,cm \cr} $$
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The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
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