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The areas of two circular fields are in the ratio 16 : 49. If the radius of the latter is 14 m, the what is the radius of the former ?
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& \frac{{\pi R_1^2}}{{\pi R_2^2}} = \frac{{16}}{{49}} \cr
& \Rightarrow \frac{{R_1^2}}{{\left( {14 \times 14} \right)}} = \frac{{16}}{{49}} \cr
& \Rightarrow R_1^2 = \frac{{14 \times 14 \times 16}}{{49}} \cr
& \Rightarrow R_1^2 = \frac{{14 \times 4}}{7} = 8\,m \cr} $$
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