The areas of two circular fields are in the ratio 16 : 49. If the radius of the latter is 14 m, the what is the radius of the former ?

A. 4 m

B. 8 m

C. 18 m

D. 32 m

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & \frac{{\pi R_1^2}}{{\pi R_2^2}} = \frac{{16}}{{49}} \cr & \Rightarrow \frac{{R_1^2}}{{\left( {14 \times 14} \right)}} = \frac{{16}}{{49}} \cr & \Rightarrow R_1^2 = \frac{{14 \times 14 \times 16}}{{49}} \cr & \Rightarrow R_1^2 = \frac{{14 \times 4}}{7} = 8\,m \cr} $$