The curved surface area and volume of a cylindrical object are 88 cm2 and 132 cm3, respectively. The height (in cm) of the cylindrical object is:
A. 3$$\frac{2}{3}$$
B. 4$$\frac{2}{3}$$
C. 6
D. 4
Answer: Option B
Solution (By Examveda Team)
Curved area of cylinder = 88 cm22πrh = 88
2 × $$\frac{{22}}{7}$$ × r × h = 88
r × h = 14
Volume of cylinder = πr2h = 132 cm3
$$\frac{{22}}{7}$$ × r2h = 132
r2h = 42
r × rh = 42
r × 14 = 42
r = 3
r × h = 14
h $$ = \frac{{14}}{3} = 4\frac{2}{3}$$
Height $$ = 4\frac{2}{3}{\text{ cm}}$$
Related Questions on Mensuration 3D
A. 1.057 cm3
B. 4.224 cm3
C. 1.056 cm3
D. 42.24 cm3
A sphere and a hemisphere have the same volume. The ratio of their curved surface area is:
A. $${2^{\frac{3}{2}}}:1$$
B. $${2^{\frac{2}{3}}}:1$$
C. $${4^{\frac{2}{3}}}:1$$
D. $${2^{\frac{1}{3}}}:1$$

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