The diagonal of a rectangle is $$\sqrt {41} $$ cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
A. 9 cm
B. 18 cm
C. 20 cm
D. 41 cm
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & \sqrt {{l^2} + {b^2}} = \sqrt {41} \cr & {\text{Also}},\,lb = 20 \cr & {\left( {l + b} \right)^2} = \left( {{l^2} + {b^2}} \right) + 2/b = 41 + 40 = 81 \cr & \Rightarrow \left( {l + b} \right) = 9 \cr & \therefore {\text{Perimeter}} = 2\left( {l + b} \right) = 18cm \cr} $$Join The Discussion
Comments ( 1 )
Related Questions on Area
A. 15360 m2
B. 153600 m2
C. 30720 m2
D. 307200 m2
E. None of these
A. 2%
B. 2.02%
C. 4%
D. 4.04%
E. None of these
A. 16 cm
B. 18 cm
C. 24 cm
D. Data inadequate
E. None of these
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
A. 40%
B. 42%
C. 44%
D. 46%
good solution for short time