The diagonal of a square is $$4\sqrt 2 $$ cm. The diagonal of another square whose area is double that of the first square, is :
A. 8 cm
B. $$8\sqrt 2 $$ cm
C. $$4\sqrt 2 $$ cm
D. 16 cm
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & d = 4\sqrt 2 \,cm \cr & \Rightarrow {\text{Area }} = \frac{1}{2}d_1^2 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{1}{2} \times {\left( {4\sqrt 2 } \right)^2} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 16}}\,{\text{c}}{{\text{m}}^2} \cr} $$Area of new square = (2 × 16) cm2 = 32 cm2
$$\eqalign{ & \therefore \frac{1}{2}d_2^2 = 32 \cr & \Rightarrow d_2^2 = 64 \cr & \Rightarrow {d_2} = 8\,cm \cr} $$
Related Questions on Area
A. 15360 m2
B. 153600 m2
C. 30720 m2
D. 307200 m2
E. None of these
A. 2%
B. 2.02%
C. 4%
D. 4.04%
E. None of these
A. 16 cm
B. 18 cm
C. 24 cm
D. Data inadequate
E. None of these
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
A. 40%
B. 42%
C. 44%
D. 46%
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