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The difference between a two-digit number and the number obtained by interchanging the two digits is 63. Which is the smaller of the two numbers ?
Answer & Solution
Correct Answer:
Option
D
Let the ten's digit be x and unit's digit be y
Then,
$$\eqalign{ & \Leftrightarrow \left( {10x + y} \right) - \left( {10y + x} \right) = 63 \cr & \Leftrightarrow 9\left( {x - y} \right) = 63 \cr & \Leftrightarrow x - y = 7 \cr} $$
Then,
$$\eqalign{ & \Leftrightarrow \left( {10x + y} \right) - \left( {10y + x} \right) = 63 \cr & \Leftrightarrow 9\left( {x - y} \right) = 63 \cr & \Leftrightarrow x - y = 7 \cr} $$
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