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The difference between two integers is 5. Their product is 500. Find the numbers.

A. 15, 20

B. 20, 25

C. 30, 25

D. 21, 26

Answer: Option B

Solution(By Examveda Team)

Let the integers be x and (x + 5)
Then,
$$\eqalign{ & \Leftrightarrow x\left( {x + 5} \right) = 500 \cr & \Leftrightarrow {x^2} + 5x - 500 = 0 \cr & \Leftrightarrow \left( {x + 25} \right)\left( {x - 20} \right) = 0 \cr & \Leftrightarrow x = 20 \cr} $$
So, the numbers are 20 and 25

This Question Belongs to Arithmetic Ability >> Problems On Numbers

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Comments ( 1 )

  1. Phurba Bhutia
    Phurba Bhutia :
    4 years ago

    X=7.then ans is 9. Solution is :X+(x+2) +(x+4) =x+20.
    3x+6=x+20
    3x-x=20-6
    2x=14
    X=14/2
    X=7.

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