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the difference between two numbers is 3 and the difference between their squares is 63. Which is the larger number ?
Answer & Solution
Correct Answer:
Option
B
Let the number be x and y
Then,
$${x^2} - {y^2} = 63\,\,\,\,\& \,\,\,\,x - y = 3$$
On dividing, we get: x + y = 21
Solving x + y = 21 and x - y = 3,
We get: x = 12 and y = 9
∴ Larger number = 12
Then,
$${x^2} - {y^2} = 63\,\,\,\,\& \,\,\,\,x - y = 3$$
On dividing, we get: x + y = 21
Solving x + y = 21 and x - y = 3,
We get: x = 12 and y = 9
∴ Larger number = 12
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